Pro Tools - Delete Unused Playlists

Hi @Zak_Cohen,

This exact question came up in the SoundFlow hangout today (asked by @Dreamcatcher_Studio ), and I found this old thread so I thought I'd answer it here.

function deleteAllUnusedPlaylists() {
    sf.ui.proTools.appActivateMainWindow();
    sf.ui.proTools.mainWindow.invalidate();

    sf.ui.proTools.selectedTrack.popupButtons.allItems[1].popupMenuSelect({
        menuPath: ["Delete Unused..."],
    });

    const deleteUnusedPlaylistsWin = sf.ui.proTools.windows.whoseTitle.is("Delete Unused Playlists").first;

    deleteUnusedPlaylistsWin.elementWaitFor();

    const deleteUnusedPlaylistsTable = deleteUnusedPlaylistsWin.tables.whoseTitle.is("List of playlists").first;

    deleteUnusedPlaylistsTable.childrenByRole("AXRow").map(row => {
        const cell = row.childrenByRole("AXCell").first;
        const staticTextBtn = cell.childrenByRole("AXStaticText").first;

        // Quirk: The playlist rows text fields need to be clicked twice for some reason otherwise every other row is selected.
        staticTextBtn.elementClick();
        staticTextBtn.elementClick();
    });

    deleteUnusedPlaylistsWin.buttons.whoseTitle.is("Delete").first.elementClick();
    deleteUnusedPlaylistsWin.elementWaitFor({waitForNoElement:true});    
}

deleteAllUnusedPlaylists();

It seems that there is a quirk when selecting the rows in the table programmatically. After trying a few things I found that clicking the static text in the rows twice, ensures the rows are selected. Nice and fast!

FYI: @Chris_Shaw, @Mike_Wax, @Owen_Granich_Young (Regs at the SoundFlow Hangout!)

Looking into this again... I'm still getting the "Could not click popup menu item (Delete Unused Playlists: Line 15" error. This script would be super helpful as I'm cleaning up a session to send to the mixer. In a perfect world, the script would comb through the session and get rid of any unused playlists on any tracks. Thoughts here?

@Matthew_Bronleewe

Sorry I'm late, but this may help you. When there are no additional playlists, the popup menu will be greyed out. I modified the code to check to see if the popup menu option exists first. I'm not sure if this is the best way to do it, but it works!

function deleteAllUnusedPlaylists() {
    sf.ui.proTools.appActivateMainWindow();

    var deletePlaylistsEnabled = sf.ui.proTools.selectedTrack.popupButtons.whoseTitle.contains('Delete Unused...').exists
    
    const deleteUnusedPlaylistsWin = sf.ui.proTools.windows.whoseTitle.is("Delete Unused Playlists").first;


        if (deletePlaylistsEnabled) {

            sf.ui.proTools.selectedTrack.popupButtons.allItems[1].popupMenuSelect({ 
            menuPath: ["Delete Unused..."],
            });

            deleteUnusedPlaylistsWin.elementWaitFor();

            const deleteUnusedPlaylistsTable = deleteUnusedPlaylistsWin.tables.whoseTitle.is("List of playlists").first;

            deleteUnusedPlaylistsTable.childrenByRole("AXRow").map(row => {
                const cell = row.childrenByRole("AXCell").first;
                const staticTextBtn = cell.childrenByRole("AXStaticText").first;

                // Quirk: The playlist rows text fields need to be clicked twice for some reason otherwise every other row is selected.
                staticTextBtn.elementClick();
                staticTextBtn.elementClick();
            });

            deleteUnusedPlaylistsWin.buttons.whoseTitle.is("Delete").first.elementClick();
            deleteUnusedPlaylistsWin.elementWaitFor({waitForNoElement:true});    
        }
        else {
            log ("No playlists to delete.")
        }
    }

deleteAllUnusedPlaylists();