Copy to playlist

I thought of that route display Playlists, copy clip to it, and folding it back into Waveform view... but i was hoping for a more elegant route.

I have the script pasted below, but there is a mistake in it somewhere. Likely a { or [ or } or }
I am not yet so familiar to the scripting language and have to browse my How To's trough other scripts and forum posts, but i fail a lot as i actually don't know what i am doing in detail.

function getPlaylistNames() {
    var playlistBtn = sf.ui.proTools.selectedTrack.popupButtons.whoseTitle.is('Playlist selector').first;
    var items = playlistBtn.popupMenuFetchAllItems().menuItems;
    sf.ui.proTools.appActivateMainWindow();
    var playlists = items.filter(function (i) { return i.names[0] === 'Target Playlist' && i.names[1] !== 'Main Playlist' }).map(function (i) { return i.names[1]; });
    return playlists;
}

var playlists = getPlaylistNames();
if (playlists.length == 1) {
    //We only have our major playlist. Create a new one
    log('create new playlist');
    sf.keyboard.press({ keys: 'shift+option+down' });
} else {
    //We already have more than one playlist. Go to the other one
    log('go to diff playlist');
    sf.ui.proTools.selectedTrack.trackDisplaySelect({
        selectForAllSelectedTracks: true,
        displayPath: ['playlists']
    });
    sf.keyboard.press({ keys: 'command+c' });
    sf.wait({ intervalMs: 100 });
    sf.keyboard.press({ keys: 'semicolon' });
    sf.wait({ intervalMs: 100 });
    sf.keyboard.press({ keys: 'command+v' });
    sf.ui.proTools.selectedTrack.trackDisplaySelect({
        selectForAllSelectedTracks: true,
        displayPath: ['waveform']
    });

    //The name of the other playlist will be in playlists[1]
}